[Leetcode/SQL] 620. Not Boring Movies

문제는 여기서 확인할 수 있습니다.

 

Table: Cinema

+----------------+----------+
| Column Name    | Type     |
+----------------+----------+
| id             | int      |
| movie          | varchar  |
| description    | varchar  |
| rating         | float    |
+----------------+----------+
id is the primary key for this table.
Each row contains information about the name of a movie, its genre, and its rating.
rating is a 2 decimal places float in the range [0, 10]

 

Write an SQL query to report the movies with an odd-numbered ID and a description that is not "boring".

Return the result table ordered by rating in descending order.

The query result format is in the following example.

 

Example 1:

Input: 
Cinema table:
+----+------------+-------------+--------+
| id | movie      | description | rating |
+----+------------+-------------+--------+
| 1  | War        | great 3D    | 8.9    |
| 2  | Science    | fiction     | 8.5    |
| 3  | irish      | boring      | 6.2    |
| 4  | Ice song   | Fantacy     | 8.6    |
| 5  | House card | Interesting | 9.1    |
+----+------------+-------------+--------+
Output: 
+----+------------+-------------+--------+
| id | movie      | description | rating |
+----+------------+-------------+--------+
| 5  | House card | Interesting | 9.1    |
| 1  | War        | great 3D    | 8.9    |
+----+------------+-------------+--------+
Explanation: 
We have three movies with odd-numbered IDs: 1, 3, and 5. The movie with ID = 3 is boring so we do not include it in the answer.

 

Code:

select *
from Cinema
where id % 2 = 1 and description <> "boring"
order by rating desc;

 

description != "boring" 이라고 해도 정답 처리가 된다.

where절에 and로 두 조건을 매우 직관적으로 써주어서 큰 어려움은 없는 문제이다.